Question

The magnetic moment of a divalent ion in aqueous solution with atomic number $25$ is

• A. $5.9B.M$
• B. $2.9B.M$
• C. $6.9B.M$
• D. $9.9B.M$

Answer 1

Answer: (A)

$\mu =\sqrt{n\left(n+2\right)}B.M.$
Electronic configuration of ion $\left(25\right)$
$=1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}3d^{5}4s^2$
No. of unpaired electrons $\left(n\right)=5$
$\mu =\sqrt{5\left(5+2\right)}=\sqrt{35}=5.9B.M.$