Question

The magnetic moment (in $BM$) of $Z{n}^{2+}$ ion according to spin-only formula is

• A. zero
• B. 1.73
• C. 2.84
• D. 3.87

Answer 1

Answer: (A)

$Z{n}^{2+}(Z=30):[Ar]3d^{10}4s^0;$
zero unpaired $e^{-}$.
Hence, its magnetic moment is zero.
$\mu =\sqrt{n(n+2)}=\sqrt{0(0+2)}\mu =0$