The magnetic flux linked with a coil (in Wb) is given by the equation φ =5t2+3t+16 The magnitude of induced emf in the coil at the fourth second will be

Question

The magnetic flux linked with a coil (in Wb) is given by the equation φ =5t2+3t+16 The magnitude of induced emf in the coil at the fourth second will be (A) 33 V (B) 43 V (C) 108 V (D) 10 V

Tardigrade Admin · Accepted Answer

φ=5t2+3t+60 |ε|=|(dφ/dt)|=10t+3 At t=4th sec |ε|=40+3=43 volt

Q. The magnetic flux linked with a coil (in Wb) is given by the equation $ϕ = 5 t^{2} + 3 t + 16$
The magnitude of induced emf in the coil at the fourth second will be

$33 V$

$43 V$

$108 V$

$10 V$

$ϕ = 5 t^{2} + 3 t + 60$
$∣ ε ∣ = ∣ ∣ \frac{d ϕ}{d t} ∣ ∣ = 10 t + 3$
At $t = 4 t h sec$
$∣ ε ∣ = 40 + 3 = 43$ volt

Q. The magnetic flux linked with a coil (in Wb) is given by the equation ϕ=5t2+3t+16 The magnitude of induced emf in the coil at the fourth second will be

33V

43V

108V

10V