The magnetic field on the axis of a circular loop of radius 100 cm carrying current I=√2 A, at point 1 m away from the centre of the loop is given by:

Question

The magnetic field on the axis of a circular loop of radius 100 cm carrying current I=√2 A, at point 1 m away from the centre of the loop is given by: (A) 3.14 × 10-7 T (B) 6.28 × 10-7 T (C) 3.14 × 10-4 T (D) 6.28 × 10-4 T

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/6fd50b8420f2c411a9adcbfe3aa0954b-.png" /> B A = B 0 sin 3 θ =(μ0 i /2 R ) × sin 3 θ =(4 π × 10-7 × √2/2 × 1) ×((1/2 √2)) B A =3.14 × 10-7 T

Q. The magnetic field on the axis of a circular loop of radius $100 c m$ carrying current $I = 2 A$ , at point $1 m$ away from the centre of the loop is given by:

$3.14 \times 1 0^{- 7} T$

$6.28 \times 1 0^{- 7} T$

$3.14 \times 1 0^{- 4} T$

$6.28 \times 1 0^{- 4} T$

$B_{A} = B_{0} sin^{3} θ$
$= \frac{μ _{0} i}{2 R} \times sin^{3} θ$
$= \frac{4 π \times 1 0 ^{- 7} \times 2}{2 \times 1} \times (\frac{1}{2 2})$
$B_{A} = 3.14 \times 1 0^{- 7} T$

Q. The magnetic field on the axis of a circular loop of radius 100cm carrying current I=2​A, at point 1m away from the centre of the loop is given by:

3.14×10−7T

6.28×10−7T

3.14×10−4T

6.28×10−4T