The magnetic field of an electromagnetic wave is given by By=3 × 10-7 sin (103 x+6.28 × 1012 t) The wavelength of the electromagnetic wave is

Question

The magnetic field of an electromagnetic wave is given by By=3 × 10-7 sin (103 x+6.28 × 1012 t) The wavelength of the electromagnetic wave is (A) 6.28 cm (B) 3.14 cm (C) 0.63 cm (D) 0.32 cm

Tardigrade Admin · Accepted Answer

Comparing the given equation with By=B0 sin (k x+ω t) We get, k=103 or (2 π/λ)=103 ∴ λ=(2 π/103) m =6.28 × 10-3 m =0.63 cm

Q. The magnetic field of an electromagnetic wave is given by $B_{y} = 3 \times 1 0^{- 7} sin (1 0^{3} x + 6.28 \times 1 0^{12} t)$ The wavelength of the electromagnetic wave is

6.28 cm

3.14 cm

0.63 cm

0.32 cm

Comparing the given equation with
$B_{y} = B_{0} sin (k x + ω t)$
We get, $k = 1 0^{3}$ or $\frac{2 π}{λ} = 1 0^{3}$
$∴ λ = \frac{2 π}{1 0 ^{3}} m = 6.28 \times 1 0^{- 3} m$
$= 0.63 c m$

Q. The magnetic field of an electromagnetic wave is given by By​=3×10−7sin(103x+6.28×1012t) The wavelength of the electromagnetic wave is