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Q. The magnetic field of an electromagnetic wave is given by $B_{y}=3 \times 10^{-7} \sin \left(10^{3} x+6.28 \times 10^{12}\, t\right)$ The wavelength of the electromagnetic wave is

Electromagnetic Waves

Solution:

Comparing the given equation with
$B_{y}=B_{0} \sin (k x+\omega t)$
We get, $k=10^{3}$ or $\frac{2 \pi}{\lambda}=10^{3}$
$\therefore \lambda=\frac{2 \pi}{10^{3}} m =6.28 \times 10^{-3} \,m $
$=0.63\, cm$