The magnetic field intensity at the centre of cubical cage of identical wires of length ‘a’ due to a current I flowing as shown in the fiigure is

Question

The magnetic field intensity at the centre of cubical cage of identical wires of length ‘a’ due to a current I flowing as shown in the fiigure is (A) (21/a) (B) (√21/a) (C) 0 (D) I/2a

Tardigrade Admin · Accepted Answer

For symmetrical current distribution, magnetic field at the centre due to all current carrying conductors will get cancelled. Hence Bnet =0

Q. The magnetic field intensity at the centre of cubical cage of identical wires of length ‘a’ due to a current I flowing as shown in the fiigure is

$\frac{21}{a}$

$\frac{21}{a}$

0

I/2a

For symmetrical current distribution, magnetic field at the centre due to all current carrying conductors will get cancelled. Hence $B_{n e t} = 0$

Q. The magnetic field intensity at the centre of cubical cage of identical wires of length ‘a’ due to a current I flowing as shown in the fiigure is

a21​

a21​​

0

I/2a

For symmetrical current distribution, magnetic field at the centre due to all current carrying conductors will get cancelled. Hence Bnet​=0

$\frac{21}{a}$

$\frac{21}{a}$

For symmetrical current distribution, magnetic field at the centre due to all current carrying conductors will get cancelled. Hence $B_{n e t} = 0$