The magnetic field due to current carrying circular loop of the radius 12 cm at its centre is 0.50× 10- 4T . The magnetic field due to this loop at a point on the axis at a distance of 5 cm from the centre is

Question

The magnetic field due to current carrying circular loop of the radius 12 cm at its centre is 0.50× 10- 4T . The magnetic field due to this loop at a point on the axis at a distance of 5 cm from the centre is (A) 3.5× 10- 9 T (B) 5.3× 10- 9 T (C) 9.3× 105 T (D) 3.9× 10- 5 T

Tardigrade Admin · Accepted Answer

Use (Ba x i s/Bc e n t r e)=((R2/R2 + x2))3 / 2 (Ba x i s/0.5 × (10)- 4)=(((12)2/(12)2 + 52))3 / 2 Ba x i s=(0.5 × (10)- 4) ((12/13))3 Ba x i s=3.9× 10- 5T

Q. The magnetic field due to current carrying circular loop of the radius $12 c m$ at its centre is $0.50 \times 1 0^{- 4} T$ . The magnetic field due to this loop at a point on the axis at a distance of $5 c m$ from the centre is

$3.5 \times 1 0^{- 9} T$

$5.3 \times 1 0^{- 9} T$

$9.3 \times 1 0^{5} T$

$3.9 \times 1 0^{- 5} T$

Use $\frac{B _{a x i s}}{B _{ce n t re}} = (\frac{R ^{2}}{R ^{2} + x ^{2}})^{3/2}$
$\frac{B _{a x i s}}{0.5 \times ( 10 ) ^{- 4}} = (\frac{( 12 ) ^{2}}{( 12 ) ^{2} + 5 ^{2}})^{3/2}$
$B_{a x i s} = (0.5 \times (10)^{- 4}) (\frac{12}{13})^{3}$
$B_{a x i s} = 3.9 \times 1 0^{- 5} T$

Q. The magnetic field due to current carrying circular loop of the radius 12cm at its centre is 0.50×10−4T . The magnetic field due to this loop at a point on the axis at a distance of 5cm from the centre is

3.5×10−9T

5.3×10−9T

9.3×105T

3.9×10−5T