The magnetic field B and the magnetic intensity H in a material are found to be 1.6 T and 1000 A / m respectively. Calculate the relative permeability μ r and the susceptibility chi of material.

Question

The magnetic field B and the magnetic intensity H in a material are found to be 1.6 T and 1000 A / m respectively. Calculate the relative permeability μ r and the susceptibility chi of material. (A) 1.3 × 10-3 each (B) 1.3 × 103 each (C) 3.1 × 10-3 each (D) 3.1 × 103 each

Tardigrade Admin · Accepted Answer

μ=(B/H)=(1.6/1000) =1.6 × 10-3 TmA -1 μ r =(μ/μ o )=(1.6 × 10-3/4 π × 10-7) =(1.6 × 10-3/4 × 3.14 × 10-7) =0.127 × 104 =1.3 × 103 chi m ⇒ μ r -1 ≈ 1.3 × 103 μ r =1.3 × 103

Q. The magnetic field $B$ and the magnetic intensity $H$ in a material are found to be $1.6 T$ and $1000 A / m$ respectively. Calculate the relative permeability $μ_{r}$ and the susceptibility $χ$ of material.

$1.3 \times 1 0^{- 3}$ each

$1.3 \times 1 0^{3}$ each

$3.1 \times 1 0^{- 3}$ each

$3.1 \times 1 0^{3}$ each

Q. The magnetic field B and the magnetic intensity H in a material are found to be 1.6T and 1000A/m respectively. Calculate the relative permeability μr​ and the susceptibility χ of material.

1.3×10−3 each

1.3×103 each

3.1×10−3 each

3.1×103 each

μ=HB​=10001.6​ =1.6×10−3TmA−1 μr​=μo​μ​=4π×10−71.6×10−3​ =4×3.14×10−71.6×10−3​ =0.127×104 =1.3×103 χm​⇒μr​−1≈1.3×103 μr​=1.3×103

Q. The magnetic field $B$ and the magnetic intensity $H$ in a material are found to be $1.6 T$ and $1000 A / m$ respectively. Calculate the relative permeability $μ_{r}$ and the susceptibility $χ$ of material.

$1.3 \times 1 0^{- 3}$ each

$1.3 \times 1 0^{3}$ each

$3.1 \times 1 0^{- 3}$ each

$3.1 \times 1 0^{3}$ each