The magnetic field at the centre C of the arrangement shown in figure is

Question

The magnetic field at the centre C of the arrangement shown in figure is (A) (μ0 i/2π r) ( 1 +π) (B) (μ0 i/ 4 π r) ( 1 +π) (C) (μ0 i/π r) ( 1 +π) (D) (μ0 i/ r) ( 1 +π)

Tardigrade Admin · Accepted Answer

According to diagram in the question, magnetic field at the centre

C

will be sum of the magnetic field due to straight part

B_{1}

and magnetic field due to rircular part

R_{2}

∵

From Maxwell's right hand thumb rule direction of both magnetic field at the point

C

will be same and above the plane of paper.
So,

B_{C} = B_{1} + B_{2} = \frac{μ _{0} i}{4 π r} + \frac{μ _{0} i}{4 r} = \frac{μ _{0} i}{4 π r} (1 + π)

Hence, the magnetic field at the centre

C

of the arrangement shown in figure is,

\frac{μ _{0}}{4 π r} i (1 + π)

.

Q. The magnetic field at the centre $C$ of the arrangement shown in figure is

$\frac{μ _{0} i}{2 π r} (1 + π)$

$\frac{μ _{0} i}{4 π r} (1 + π)$

$\frac{μ _{0} i}{π r} (1 + π)$

$\frac{μ _{0} i}{r} (1 + π)$

Q. The magnetic field at the centre C of the arrangement shown in figure is

2πrμ0​i​(1+π)

4πrμ0​i​(1+π)

πrμ0​i​(1+π)

rμ0​i​(1+π)

Q. The magnetic field at the centre $C$ of the arrangement shown in figure is

$\frac{μ _{0} i}{2 π r} (1 + π)$

$\frac{μ _{0} i}{4 π r} (1 + π)$

$\frac{μ _{0} i}{π r} (1 + π)$

$\frac{μ _{0} i}{r} (1 + π)$