The magnetic field at a perpendicular distance of 2 cm from an infinite straight current carrying conductor is 2 × 10-6 T. The current in the wire is

Question

The magnetic field at a perpendicular distance of 2 cm from an infinite straight current carrying conductor is 2 × 10-6 T. The current in the wire is (A) 0.1 A (B) 0.2 A (C) 0.4 A (D) 0.8 A

Tardigrade Admin · Accepted Answer

The magnetic field due to a infinite straight curren carrying conductor at a perpendicular distance

r

from it is given by

B = \frac{μ _{0}}{4 π} \frac{2 I}{r}

Substituting the given values, we get

2 \times 1 0^{- 6} = \frac{1 0 ^{- 7} \times 2 \times I}{0.02}

,

I = \frac{2 \times 1 0 ^{- 6} \times 0.02}{1 0 ^{- 7} \times 2} = 0.2 A

Q. The magnetic field at a perpendicular distance of 2cm from an infinite straight current carrying conductor is 2×10−6T. The current in the wire is

0.1 A

0.2 A

0.4 A

0.8 A

The magnetic field due to a infinite straight curren carrying conductor at a perpendicular distance r from it is given by B=4πμ0​​r2I​ Substituting the given values, we get 2×10−6=0.0210−7×2×I​, I=10−7×22×10−6×0.02​=0.2A

Q. The magnetic field at a perpendicular distance of $2 c m$ from an infinite straight current carrying conductor is $2 \times 1 0^{- 6} T$ . The current in the wire is