The lowest resistance which can be obtained by connecting 10 resistors each of 1 / 10 ohm is

Question

The lowest resistance which can be obtained by connecting 10 resistors each of 1 / 10 ohm is (A) 1 / 250 Ω (B) 1 / 200 Ω (C) 1 / 100 Ω (D) 1 / 10 Ω

Tardigrade Admin · Accepted Answer

Lowest resistance will be in the case when all the resistors are connected in parallel. (1/R)=(1/0.1)+(1/0.1) ldots 10 times (1/R)=10+10 ldots ldots .10 times (1/R)=100 or R=(1/100) Ω

Q. The lowest resistance which can be obtained by connecting 10 resistors each of $1/10 o hm$ is

$1/250 Ω$

$1/200 Ω$

$1/100 Ω$

$1/10 Ω$

Lowest resistance will be in the case when all the resistors are connected in parallel.
$\frac{1}{R} = \frac{1}{0.1} + \frac{1}{0.1} \dots 10$ times
$\frac{1}{R} = 10 + 10 \dots\dots .10$ times
$\frac{1}{R} = 100$ or $R = \frac{1}{100} Ω$

Q. The lowest resistance which can be obtained by connecting 10 resistors each of 1/10ohm is

1/250Ω

1/200Ω

1/100Ω

1/10Ω