Let the two tangents to the parabola y2=4ax be PT and QT
which are at right angle to one another at T(h,k).
Then we have a find the locus of T(h,k).
We know that y=mx+ma,
where m is the slope is the equation of tangent to the parabola y2=4ax for all m.
Since this tangent to the parabola will pass through T(h,k),
so k=mh+ma;
or m2h−mk+a=0
This is a quadratic equation in m,
so will have two roots, say m1 and m2,
then m1+m2=hk,
and m1⋅m2=ha
Given that the two tangents intersect at right angle so m1⋅m2=−1
or ha=−1
or h+a=0
The locus of T(h,k) is x+a=0,
which is the equation of directrix.