The load versus elongation graph for four wires of same length and the same material is shown in figure. The thinnest wire is represented by line

Question

The load versus elongation graph for four wires of same length and the same material is shown in figure. The thinnest wire is represented by line (A) OC (B) OD (C) OA (D) OB

Tardigrade Admin · Accepted Answer

For the same load wire with maximum elongation has minimum cross-section area <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/75065d30c3d97b172b87d58dc6c482af-.png" /> As (F L/A Y)=Δ x F, L, Y are fixed s o (1/A) propto Δ x ⇒ O A is the thinnest

Q. The load versus elongation graph for four wires of same length and the same material is shown in figure. The thinnest wire is represented by line

OC

OD

OA

OB

For the same load wire with maximum elongation has minimum cross-section area

As $\frac{F L}{A Y} = Δ x$
$F, L, Y$ are fixed $so \frac{1}{A} \propto Δ x$
$\Rightarrow O A$ is the thinnest

Q. The load versus elongation graph for four wires of same length and the same material is shown in figure. The thinnest wire is represented by line

OC

OD

OA

OB

For the same load wire with maximum elongation has minimum cross-section area As AYFL​=Δx F,L,Y are fixed soA1​∝Δx ⇒OA is the thinnest

For the same load wire with maximum elongation has minimum cross-section area

As $\frac{F L}{A Y} = Δ x$
$F, L, Y$ are fixed $so \frac{1}{A} \propto Δ x$
$\Rightarrow O A$ is the thinnest