Question

The line $(3x-y+5)+\lambda (2x-3y-4)=0$ will be parallel to $y$ -axis, if $\lambda =$

• A. $\frac{1}{3}$
• B. $\frac{-1}{3}$
• C. $\frac{3}{2}$
• D. $\frac{-3}{2}$

Answer 1

Answer: (B)

The given line can be written in this form
$(3+2\lambda )x+(-1-3\lambda )y+(5-4\lambda )=0$
It will be parallel to y-axis, if
$-1-3\lambda =0$
$\Rightarrow \lambda =-\frac{1}{3}$