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Q.
The line $(3 x-y+5)+\lambda(2 x-3 y-4)=0$ will be parallel to $y$ -axis, if $\lambda=$
Straight Lines
Solution:
The given line can be written in this form
$(3+2 \lambda) x+(-1-3 \lambda) y+(5-4 \lambda)=0$
It will be parallel to y-axis, if
$-1-3 \lambda=0 $
$\Rightarrow \lambda=-\frac{1}{3}$