The limbs of a U-tube are vertical and have internal diameters 0.5 cm and 1 cm respectively. If the tube contains water, what will be the difference in the surface level in the limbs? (Surface tension of water = 72 dyne/cm)

Question

The limbs of a U-tube are vertical and have internal diameters 0.5 cm and 1 cm respectively. If the tube contains water, what will be the difference in the surface level in the limbs? (Surface tension of water = 72 dyne/cm) (A) 0.2938 cm (B) 0.8938 cm (C) 0.6938 cm (D) None of these

Tardigrade Admin · Accepted Answer

For wider limb, h1 (2 T/r1 d g) For the narrow limb, h2 (2 T/r2 d g) h2-h1 (2 T/d g)((1/r2)-(1/r1))=(2 × 72/1 × 980)((1/0.25)-(1/0.5)) =(2 × 72/980) × (0.25/0.25 × 0.5)=0.2938 cm

Q. The limbs of a U-tube are vertical and have internal diameters 0.5cm and 1cm respectively. If the tube contains water, what will be the difference in the surface level in the limbs? (Surface tension of water =72 dyne/cm)

0.2938 cm

0.8938 cm

0.6938 cm

None of these

For wider limb, h1​r1​dg2T​ For the narrow limb, h2​r2​dg2T​ h2​−h1​dg2T​(r2​1​−r1​1​)=1×9802×72​(0.251​−0.51​) =9802×72​×0.25×0.50.25​=0.2938cm

Q. The limbs of a U-tube are vertical and have internal diameters $0.5 c m$ and $1 c m$ respectively. If the tube contains water, what will be the difference in the surface level in the limbs? (Surface tension of water $= 72$ dyne/cm)