Question

The Lewis structure for $O_3$ molecule is given below. The correct formal charges on oxygen atoms labelled $1,2,3$ are respectively.

• A. -1,0,+1
• B. +1,0,-1
• C. +1,-1,0
• D. 0,+1,-1

Answer 1

Answer: (A)

$\because$ Formal charge $=$ number of valency electron

- [(number of $1p+\frac{1}{2}$ number of bp of electron].

$lp=$ lone pair of electrons

$bp=$ bond pair of electrons

$\therefore$ For



$F.C$ for $O_{(1)}=6-[6+1]=-1$

$F.C$ for $O_{(2)}=6-[4+2]=0$

$F.C$ for $O_{(3)}=6-[2+3]=+1$