The lengths of two opposite edges of tetrahedron are 2 and 3 units and shortest distance between them is equal to 4 units and angle between them is (π/6), then volume of tetrahedron is greater than or equal to

Question

The lengths of two opposite edges of tetrahedron are 2 and 3 units and shortest distance between them is equal to 4 units and angle between them is (π/6), then volume of tetrahedron is greater than or equal to (A) 1 (B) 2 (C) 7 (D) 8

Tardigrade Admin · Accepted Answer

Volume of tetrahedron =(1/6) × 2 × 3 × 4 sin (π/6)=2 cubic units.

Q. The lengths of two opposite edges of tetrahedron are 2 and 3 units and shortest distance between them is equal to 4 units and angle between them is $\frac{π}{6}$ , then volume of tetrahedron is greater than or equal to

1

2

7

8

Volume of tetrahedron $= \frac{1}{6} \times 2 \times 3 \times 4 sin \frac{π}{6} = 2$ cubic units.

Q. The lengths of two opposite edges of tetrahedron are 2 and 3 units and shortest distance between them is equal to 4 units and angle between them is 6π​, then volume of tetrahedron is greater than or equal to

1

2

7

8

Volume of tetrahedron =61​×2×3×4sin6π​=2 cubic units.

Q. The lengths of two opposite edges of tetrahedron are 2 and 3 units and shortest distance between them is equal to 4 units and angle between them is $\frac{π}{6}$ , then volume of tetrahedron is greater than or equal to

Volume of tetrahedron $= \frac{1}{6} \times 2 \times 3 \times 4 sin \frac{π}{6} = 2$ cubic units.