The length of the second's pendulum on the surface of the earth is 1 m . If the acceleration due to gravity on the surface of the moon is one-sixth of the acceleration due to gravity of the earth, then the length of the second's pendulum on the surface of the moon will be

Question

The length of the second's pendulum on the surface of the earth is 1 m . If the acceleration due to gravity on the surface of the moon is one-sixth of the acceleration due to gravity of the earth, then the length of the second's pendulum on the surface of the moon will be (A) (1/6 )m (B) 6 m (C) (1/36 )m (D) 36 m

Tardigrade Admin · Accepted Answer

Seconds pendulum is a special pendulum having a time period of

2 s

.
Using the formula

T = 2 π \frac{L}{g}

If the time period remains the same and

g

is reduced by a factor of

6

.
L should be reduced by a factor of 6.

\Rightarrow L = \frac{1}{6} m

on moon.

Q. The length of the second's pendulum on the surface of the earth is $1 m$ . If the acceleration due to gravity on the surface of the moon is one-sixth of the acceleration due to gravity of the earth, then the length of the second's pendulum on the surface of the moon will be

$\frac{1}{6} m$

$6 m$

$\frac{1}{36} m$

$36 m$

Seconds pendulum is a special pendulum having a time period of $2 s$ .
Using the formula $T = 2 π \frac{L}{g}$
If the time period remains the same and $g$ is reduced by a factor of $6$ .
L should be reduced by a factor of 6.
$\Rightarrow L = \frac{1}{6} m$ on moon.

Q. The length of the second's pendulum on the surface of the earth is 1m . If the acceleration due to gravity on the surface of the moon is one-sixth of the acceleration due to gravity of the earth, then the length of the second's pendulum on the surface of the moon will be

61​m

6m

361​m

36m