Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
The length of the latus rectum of the parabola 4x2-4y+8x-1=0 is
Q. The length of the latus rectum of the parabola
4
x
2
−
4
y
+
8
x
−
1
=
0
is
78
164
NTA Abhyas
NTA Abhyas 2022
Report Error
Answer:
1
Solution:
4
x
2
−
4
y
+
8
x
−
1
=
0
Rewriting the given equation of parabola similar to standard form,
⇒
4
(
x
+
1
)
2
=
4
y
+
5
⇒
(
x
+
1
)
2
=
(
y
+
4
5
)
This is of form
x
2
=
4
b
y
⇒
L
.
R
.
=
1
(length of the Latus Rectum of
x
2
=
4
b
y
is
4
b
)