The length of the diameter of the circle which touches the x-axis at the point (1, 0) and passes through the point (2, 3) is :

Question

The length of the diameter of the circle which touches the x-axis at the point (1, 0) and passes through the point (2, 3) is : (A) (10 /3 ) (B) ( 3/ 5) (C) (6 / 5) (D) ( 5/3 )

Tardigrade Admin · Accepted Answer

Now h2 = (1 - 2)2 + (h - 3)2 0 = 1 - 6h + 9 6h = 10 h = (5/3) Now diameter is 2h = (10/3)

Q. The length of the diameter of the circle which touches the x-axis at the point (1, 0) and passes through the point (2, 3) is :

$\frac{10}{3}$

$\frac{3}{5}$

$\frac{6}{5}$

$\frac{5}{3}$

Now
$h^{2} = (1 - 2)^{2} + (h - 3)^{2}$
$0 = 1 - 6 h + 9$
$6 h = 10$
$h = \frac{5}{3}$
Now diameter is $2 h = \frac{10}{3}$