The length of the chord of the parabola, y2=12 x passing through the vertex making an angle of 60° with the axis of x is:

Question

The length of the chord of the parabola, y2=12 x passing through the vertex making an angle of 60° with the axis of x is: (A) 8 (B) 4 (C) 16/3 (D) none of these

Tardigrade Admin · Accepted Answer

Length of chord =(4/m2) √a(a-m c)(1+m2) m= tan 60°=√3 Length of chord =(4/3) √3(3-√3 × 0)(1+3)=(4/3) √36=8

Q. The length of the chord of the parabola, $y^{2} = 12 x$ passing through the vertex \& making an angle of $6 0^{\circ}$ with the axis of $x$ is:

8

4

16/3

none of these

Length of chord $= \frac{4}{m ^{2}} a (a - m c) (1 + m^{2})$
$m = tan 6 0^{\circ} = 3$
Length of chord $= \frac{4}{3} 3 (3 - 3 \times 0) (1 + 3) = \frac{4}{3} 36 = 8$

Q. The length of the chord of the parabola, y2=12x passing through the vertex \& making an angle of 60∘ with the axis of x is:

8

4

16/3

none of these

Length of chord =m24​a(a−mc)(1+m2)​ m=tan60∘=3​ Length of chord =34​3(3−3​×0)(1+3)​=34​36​=8

Q. The length of the chord of the parabola, $y^{2} = 12 x$ passing through the vertex \& making an angle of $6 0^{\circ}$ with the axis of $x$ is:

Length of chord $= \frac{4}{m ^{2}} a (a - m c) (1 + m^{2})$
$m = tan 6 0^{\circ} = 3$
Length of chord $= \frac{4}{3} 3 (3 - 3 \times 0) (1 + 3) = \frac{4}{3} 36 = 8$