Question

The length of a vertical pole at the surface of a lake of water $\left(\mu =\frac{4}{3}\right)$ is $24cm$. Then to an under-water fish just below the water surface the tip of the pole appears to be

• A. 18 cm above the surface
• B. 24 cm above the surface
• C. 32 cm above the surface
• D. 36 cm above the surface

Answer 1

Answer: (C)

$\mu =\frac{\text{ Apparent height }}{\text{ Real height }}$
Now, real height $=24cm$ and $\mu =\frac{4}{3}$
$\frac{4}{3}\times 24=$ Apparent height
$\therefore$ Apparent height $=32cm$