Question

The length of a vertical pole at the surface of a lake of water $\left(\mu=\frac{4}{3}\right)$ is $24\, cm$. Then to an under-water fish just below the water surface the tip of the pole appears to be

• A. 18 cm above the surface
• B. 24 cm above the surface
• C. 32 cm above the surface
• D. 36 cm above the surface

Answer 1

Answer: (C)

$\mu=\frac{\text { Apparent height }}{\text { Real height }}$
Now, real height $=24 \,cm$ and $\mu=\frac{4}{3}$
$\frac{4}{3} \times 24=$ Apparent height
$\therefore $ Apparent height $=32\, cm$