The length of a microscope tube is 20 cm . The focal length of the objective and eye lens are 0.5 cm and 1 cm . The magnifying power of the microscope is about:

Question

The length of a microscope tube is 20 cm . The focal length of the objective and eye lens are 0.5 cm and 1 cm . The magnifying power of the microscope is about: (A) 500 (B) 10000 (C) 1000 (D) 1500

Tardigrade Admin · Accepted Answer

As we know the relation, m =( LD / f 0 f e) m =(20 × 25/0.5 × 1) m =10000

Q. The length of a microscope tube is $20 c m .$ The focal length of the objective and eye lens are $0.5 c m$ and $1 c m .$ The magnifying power of the microscope is about:

500

10000

1000

1500

As we know the relation,
$m = \frac{L D}{f _{0} f _{e}}$
$m = \frac{20 \times 25}{0.5 \times 1}$
$m = 10000$

Q. The length of a microscope tube is 20cm. The focal length of the objective and eye lens are 0.5cm and 1cm. The magnifying power of the microscope is about:

500

10000

1000

1500

As we know the relation, m=f0​fe​LD​ m=0.5×120×25​ m=10000

Q. The length of a microscope tube is $20 c m .$ The focal length of the objective and eye lens are $0.5 c m$ and $1 c m .$ The magnifying power of the microscope is about:

As we know the relation,
$m = \frac{L D}{f _{0} f _{e}}$
$m = \frac{20 \times 25}{0.5 \times 1}$
$m = 10000$