The length of a metal wire is l1 when the tension in it is F1 and l2 when the tension is F2 . Then, original length of the wire is

Question

The length of a metal wire is l1 when the tension in it is F1 and l2 when the tension is F2 . Then, original length of the wire is (A)  (l1F1+l2 f2/F1+F2)  (B)  (l1-l2/F2-F1)  (C)  (l1F2-l2 F1/F2-F1)  (D)  (l1F1-l2 F2/F2-F1)

Tardigrade Admin · Accepted Answer

As, F α Δ l where, Δ 1= change in length Now, suppose the origin length of the metal wire is l then, F1 propto(l1-l) Similarly, F2 propto(12-1) The ratio, (F1/F2)=(l1-1/l2-1) ⇒ F1 l2-F1 l=F2 l1-F2 l ⇒ (F2-F1) I=F2 l1-F1 l2 ⇒ l=(F2 I1-F1 I2/F2-F1)

Q. The length of a metal wire is $l_{1}$ when the tension in it is $F_{1}$ and $l_{2}$ when the tension is $F_{2}$ . Then, original length of the wire is

$\frac{l _{1} F _{1} + l _{2} f _{2}}{F _{1} + F _{2}}$

$\frac{l _{1} - l _{2}}{F _{2} - F _{1}}$

$\frac{l _{1} F _{2} - l _{2} F _{1}}{F _{2} - F _{1}}$

$\frac{l _{1} F _{1} - l _{2} F _{2}}{F _{2} - F _{1}}$

Q. The length of a metal wire is l1​ when the tension in it is F1​ and l2​ when the tension is F2​ . Then, original length of the wire is

F1​+F2​l1​F1​+l2​f2​​

F2​−F1​l1​−l2​​

F2​−F1​l1​F2​−l2​F1​​

F2​−F1​l1​F1​−l2​F2​​

Q. The length of a metal wire is $l_{1}$ when the tension in it is $F_{1}$ and $l_{2}$ when the tension is $F_{2}$ . Then, original length of the wire is

$\frac{l _{1} F _{1} + l _{2} f _{2}}{F _{1} + F _{2}}$

$\frac{l _{1} - l _{2}}{F _{2} - F _{1}}$

$\frac{l _{1} F _{2} - l _{2} F _{1}}{F _{2} - F _{1}}$

$\frac{l _{1} F _{1} - l _{2} F _{2}}{F _{2} - F _{1}}$