The length l, breadth b, and thickness t of a block of wood were measured with the help of a measuring scale. The results with permissible errors (in cm ) are l=15.12 ± 0.01, b=10.15 ± 0.01, and t=5.28 ± 0.01 The percentage error in volume up to proper significant figures is

Question

The length l, breadth b, and thickness t of a block of wood were measured with the help of a measuring scale. The results with permissible errors (in cm ) are l=15.12 ± 0.01, b=10.15 ± 0.01, and t=5.28 ± 0.01 The percentage error in volume up to proper significant figures is (A) 0.28 % (B) 0.35 % (C) 0.48 % (D) 0.64 %

Tardigrade Admin · Accepted Answer

Percentage error in volume is (0.01/15.12) × 100+(0.01/10.15) × 100+(0.01/5.28) × 100=0.35 %

$0.28%$

$0.35%$

$0.48%$

$0.64%$

Percentage error in volume is
$\frac{0.01}{15.12} \times 100 + \frac{0.01}{10.15} \times 100 + \frac{0.01}{5.28} \times 100 = 0.35%$

Q. The length l, breadth b, and thickness t of a block of wood were measured with the help of a measuring scale. The results with permissible errors (in cm ) are l=15.12±0.01,b=10.15±0.01, and t=5.28±0.01 The percentage error in volume up to proper significant figures is

0.28%

0.35%

0.48%

0.64%

Percentage error in volume is 15.120.01​×100+10.150.01​×100+5.280.01​×100=0.35%

$0.28%$

$0.35%$

$0.48%$

$0.64%$

Percentage error in volume is
$\frac{0.01}{15.12} \times 100 + \frac{0.01}{10.15} \times 100 + \frac{0.01}{5.28} \times 100 = 0.35%$