The least count of a stopwatch is 0.2 s . The time of 20 oscillations of a pendulum is measured to be 25 s . The percentage error in the measurement of the time period will be

Question

The least count of a stopwatch is 0.2 s . The time of 20 oscillations of a pendulum is measured to be 25 s . The percentage error in the measurement of the time period will be (A) 8 % (B) 1.8 % (C) 0.8 % (D) 0.1 %

Tardigrade Admin · Accepted Answer

percentage error = (l e a s t c o u n t/T o t a l t i m e)× 100 (0.2/25)× 100=0.8 %

Q. The least count of a stopwatch is $0.2 s$ . The time of $20$ oscillations of a pendulum is measured to be $25 s$ . The percentage error in the measurement of the time period will be

$8%$

$1.8%$

$0.8%$

$0.1%$

$p erce n t a g e error = \frac{l e a s t co u n t}{T o t a l t im e} \times 100$
$\frac{0.2}{25} \times 100 = 0.8%$

Q. The least count of a stopwatch is 0.2s . The time of 20 oscillations of a pendulum is measured to be 25s . The percentage error in the measurement of the time period will be

8%

1.8%

0.8%

0.1%