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Q. The least count of a stopwatch is $0.2 \, s$ . The time of $20$ oscillations of a pendulum is measured to be $25 \, s$ . The percentage error in the measurement of the time period will be

NTA AbhyasNTA Abhyas 2022

Solution:

$percentage \, error \, = \, \frac{l e a s t \, c o u n t}{T o t a l \, t i m e}\times 100$
$\frac{0.2}{25}\times 100=0.8\%$