Question

The LCM and the HCF of two numbers are 1001 and 7 , respectively. How many such pairs are possible?

• A. 0
• B. 1
• C. 2
• D. 7

Answer 1

Answer: (C)

Given $LCM=1001$ and $HCF=7$
Let the two numbers be $x$ and $\gamma$.
$\therefore x=7a$ and $y=7b$, where $a$ and $b$ are co-primes.
We have, $x\times y=LCM\times HCF$ $7a\times 7b=1001\times 7$ $ab=143\Rightarrow (a,b)=(1,143)$ or $(11,13)$ $\Rightarrow$ There are two pairs of numbers.