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Question
Mathematics
The last two digits of 17256 is
Q. The last two digits of
1
7
256
is
308
223
Binomial Theorem
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A
18
B
81
C
71
D
17
Solution:
1
7
256
=
(
1
7
2
)
128
=
(
290
−
1
)
128
=
1000
m
+
128
C
2
(
290
)
2
−
128
C
1
(
290
)
+
1
=
1000
(
m
+
683527
)
+
681
∴
last two digits
=
81