Question

The last digit of number $7^{886}$ is

• A. 9
• B. 7
• C. 3
• D. 1

Answer 1

Answer: (A)

Since, $7^1=7$
$7^2=49,7^3=343,7^4=2401$
$\therefore 7^{886}={\left(7^4\right)}^{221}{7}^2$
$\therefore$ The last digit number $7^{886}$ is $9$