The largest integral value of b for which the roots of quadratic equation x2+(1-b) x+(b-5)=0 are opposite in sign, is

Question

The largest integral value of b for which the roots of quadratic equation x2+(1-b) x+(b-5)=0 are opposite in sign, is (A) 5 (B) 4 (C) 3 (D) 2

Tardigrade Admin · Accepted Answer

Let f(x)=x2+(1-h) x+(h-5) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/1e7d6c15d9fed1a2cba875eef7d6d76e-.png" /> ⇒ f (0)< 0 ⇒ b -5< 0 ⇒ b < 5 ∴ b text Largest integer =0004

Q. The largest integral value of $b$ for which the roots of quadratic equation $x^{2} + (1 - b) x + (b - 5) = 0$ are opposite in sign, is

5

4

3

2

Let $f (x) = x^{2} + (1 - h) x + (h - 5)$

$\Rightarrow f (0) < 0$
$\Rightarrow b - 5 < 0 \Rightarrow b < 5$
$∴ b_{Largest integer} = 0004$

Q. The largest integral value of b for which the roots of quadratic equation x2+(1−b)x+(b−5)=0 are opposite in sign, is

5

4

3

2

Let f(x)=x2+(1−h)x+(h−5) ⇒f(0)<0 ⇒b−5<0⇒b<5 ∴bLargest integer ​=0004

Q. The largest integral value of $b$ for which the roots of quadratic equation $x^{2} + (1 - b) x + (b - 5) = 0$ are opposite in sign, is

Let $f (x) = x^{2} + (1 - h) x + (h - 5)$

$\Rightarrow f (0) < 0$
$\Rightarrow b - 5 < 0 \Rightarrow b < 5$
$∴ b_{Largest integer} = 0004$