The K H value (K bar) of Argon (I), Carbondioxide (II) formuldehyde (III) and methane (IV) are respectively 40.3,1,67,1.83 × 10-5 and 0.413 at 298 K. The increasing order of solubility of gas in liquid is

Question

The K H value (K bar) of Argon (I), Carbondioxide (II) formuldehyde (III) and methane (IV) are respectively 40.3,1,67,1.83 × 10-5 and 0.413 at 298 K. The increasing order of solubility of gas in liquid is (A) I < II < IV < III (B) III < IV < II < I (C) I < III < II < IV (D) I < IV < II < III

Tardigrade Admin · Accepted Answer

K H is inversely proportional to solubility of gas in liquid.

Q. The $K_{H}$ value (K bar) of Argon (I), Carbondioxide (II) formuldehyde (III) and methane (IV) are respectively $40.3, 1, 67, 1.83 \times 1 0^{- 5}$ and $0.413$ at $298 K$ . The increasing order of solubility of gas in liquid is

$I < II < I V < III$

$III < I V < II < I$

$I < III < II < I V$

$I < I V < II < III$

$K_{H}$ is inversely proportional to solubility of gas in liquid.

Q. The KH​ value (K bar) of Argon (I), Carbondioxide (II) formuldehyde (III) and methane (IV) are respectively 40.3,1,67,1.83×10−5 and 0.413 at 298K. The increasing order of solubility of gas in liquid is

I<II<IV<III

III<IV<II<I

I<III<II<IV

I<IV<II<III