The Kα X -ray emission line of tungsten occurs at λ= 0.021 nm , The energy difference between K and L levels in this atom is about

Question

The Kα X -ray emission line of tungsten occurs at λ= 0.021 nm , The energy difference between K and L levels in this atom is about (A)  0.51 MeV  (B)  1.2 MeV  (C)  59 keV  (D)  13.6 eV

Tardigrade Admin · Accepted Answer

Line Kα corresponds to transfer of electron from L -shell to K -shell. Here, λ =0.021 nm =2.1 × 10-11 m =(h c/E)=(h c/e E( eV )) ⇒ E( eV ) =(h c/e λ)=(6.63 × 10-34 × 3 × 108/1.6 × 10-19 × 2.1 × 10-11) eV =5.9 × 104 eV =59 keV

Q. The $K_{α} X$ -ray emission line of tungsten occurs at $λ = 0.021 nm$ , The energy difference between $K$ and $L$ levels in this atom is about

$0.51 M e V$

$1.2 M e V$

$59 k e V$

$13.6 e V$

Q. The Kα​X -ray emission line of tungsten occurs at λ=0.021nm , The energy difference between K and L levels in this atom is about

0.51MeV

1.2MeV

59keV

13.6eV

Line Kα​ corresponds to transfer of electron from L -shell to K -shell. Here, λ=0.021nm =2.1×10−11m=Ehc​=eE(eV)hc​ ⇒E(eV)=eλhc​=1.6×10−19×2.1×10−116.63×10−34×3×108​eV =5.9×104eV=59keV

Q. The $K_{α} X$ -ray emission line of tungsten occurs at $λ = 0.021 nm$ , The energy difference between $K$ and $L$ levels in this atom is about

$0.51 M e V$

$1.2 M e V$

$59 k e V$

$13.6 e V$