The Kα X -ray emission line of tungsten occurs at λ =0.021nm . The energy difference between K and L levels in this atom is about

Question

The Kα X -ray emission line of tungsten occurs at λ =0.021nm . The energy difference between K and L levels in this atom is about (A) 0.51MeV (B) 1.2MeV (C) 59keV (D) 13.6eV

Tardigrade Admin · Accepted Answer

λ kα =0.021nm=0.21 overset° A The wavelength λ kα corresponds to the transition of an electron from L shell to K shell. The energy is expressed as E=(h c/λ ) Therefore, EL-EK=(12375/λ (in overset° A))eV=(12375/0 . 21)≈58928eV or Δ E=59keV .

Q. The $K_{α}$ $X$ -ray emission line of tungsten occurs at $λ = 0.021 nm$ . The energy difference between $K$ and $L$ levels in this atom is about

$0.51 M e V$

$1.2 M e V$

$59 k e V$

$13.6 e V$

Q. The Kα​ X -ray emission line of tungsten occurs at λ=0.021nm . The energy difference between K and L levels in this atom is about

0.51MeV

1.2MeV

59keV

13.6eV

λkα​​=0.021nm=0.21A∘ The wavelength λkα​​ corresponds to the transition of an electron from L shell to K shell. The energy is expressed as E=λhc​ Therefore, EL​−EK​=λ(inA∘)12375​eV=0.2112375​≈58928eV or ΔE=59keV .

Q. The $K_{α}$ $X$ -ray emission line of tungsten occurs at $λ = 0.021 nm$ . The energy difference between $K$ and $L$ levels in this atom is about

$0.51 M e V$

$1.2 M e V$

$59 k e V$

$13.6 e V$