The Kα line obtained for molybdenum (.Z=42.) is 0.71 overset° A . Then, the wavelength of the Kα line of copper (.Z=29.) is

Question

The Kα line obtained for molybdenum (.Z=42.) is 0.71 overset° A . Then, the wavelength of the Kα line of copper (.Z=29.) is (A)  text2.14 overset° A (B)  text1.52 overset° A (C)  text1.04 overset° A (D)  text0.71 overset° A

Tardigrade Admin · Accepted Answer

λ min propto (1/(Z-1)2) ∴ (λ Cu /λ Mo )=((Z M 0-1)2/(Z Cu -1)2)=(4 l 2/(28)2)=2.14 ∴ λ Cu =2.14 × 0.71 A =1.52 A

Q. The $K_{α}$ line obtained for molybdenum $(Z = 42)$ is $0.71 A^{\circ}$ . Then, the wavelength of the $K_{α}$ line of copper $(Z = 29)$ is

$2.14 A^{\circ}$

$1.52 A^{\circ}$

$1.04 A^{\circ}$

$0.71 A^{\circ}$

$λ_{m i n} \propto \frac{1}{( Z - 1 ) ^{2}}$
$∴ \frac{λ _{C u}}{λ _{M o}} = \frac{( Z _{M_{0}} - 1 ) ^{2}}{( Z _{C u} - 1 ) ^{2}} = \frac{4 l ^{2}}{( 28 ) ^{2}} = 2.14$
$∴ λ_{C u} = 2.14 \times 0.71 A = 1.52 A$

Q. The Kα​ line obtained for molybdenum (Z=42) is 0.71A∘ . Then, the wavelength of the Kα​ line of copper (Z=29) is

2.14 A∘

1.52 A∘

1.04 A∘

0.71 A∘