Question

The joule $\times$ second is the unit of

• A. energy
• B. linear momentum
• C. angular momentum
• D. power

Answer 1

Answer: (C)

Joule is the SI unit of work and second is the SI unit of time.
$\therefore$ [Work][Time] $=\left[M{L}^2{T}^{-2}\right][T]=\left[M{L}^2{T}^{-1}\right]$
[Angular momentum] $=[M{L}^2{T}^{-1}]$