Question

The joint equation of the bisectors of the angles between the lines represented by the equation $a{x}^2+hxy+b{y}^2=0$ is

• A. $\frac{x^2-y^2}{a-b}=\frac{2xy}{h}$
• B. $\frac{x^2+y^2}{a+b}=\frac{xy}{2h}$
• C. $\frac{x^2-y^2}{a-b}=\frac{xy}{h}$
• D. None of these

Answer 1

Answer: (A)

Given, equation of pair of lines is
$a{x}^2+hxy+b{y}^2=0$
$\therefore$ Equation of angle bisector is
$\frac{x^2-y^2}{a-b}=\frac{xy}{h/2},=\frac{2xy}{h}$