Question

The joint equation of the bisectors of the angles between the lines represented by the equation $ a{{x}^{2}}+hxy+b{{y}^{2}}=0 $ is

• A. $ \frac{{{x}^{2}}-{{y}^{2}}}{a-b}=\frac{2xy}{h} $
• B. $ \frac{{{x}^{2}}+{{y}^{2}}}{a+b}=\frac{xy}{2h} $
• C. $ \frac{{{x}^{2}}-{{y}^{2}}}{a-b}=\frac{xy}{h} $
• D. None of these

Answer 1

Answer: (A)

Given, equation of pair of lines is
$ a{{x}^{2}}+hxy+b{{y}^{2}}=0 $
$ \therefore $ Equation of angle bisector is
$ \frac{{{x}^{2}}-{{y}^{2}}}{a-b}=\frac{xy}{h/2},=\frac{2xy}{h} $