Question

The coordination number of $N{i}^{2+}$ is 4 .
$NiC{l}_2+KCN\text{ (excess) }⟶A\text{ (cyano complex) }$
$NiC{l}_2+\text{ conc. }HCl\text{ (excess) }⟶B\text{ (chloro complex) }$
The IUPAC name of A and B are
(a) potassium tetracyanonickelate (II), potassium tetrachloronickelate (II)
(b) tetracyanopotassiumnickelate (II). tetrachloropotassiumnickelate (II)
(c) tetracyanonickel (II), tetrachloronickel (II)
(d) potassium tetracyanonickel (II), potassium tetrachloromickel (II)

• A. potassium tetracyanonickelate (II), potassium tetrachloronickelate (II)
• B. tetracyanopotassiumnickelate (II), tetrachloropotassiumnickelate (II)
• C. tetracyanonickel (II), tetrachloronickel (II)
• D. potassium tetracyanonickel (II), potassium tetrachloronickel (II)

Answer 1

Answer: (A)

A = $K_2[Ni(CN{)}_4];B=K_2[NiC{l}_4]$
A : Potassium tetracyanonickelate (II)
B : Potassium tetrachloronickelate (II)