Question

The coordination number of $Ni ^{2+}$ is 4 .
$NiCl _{2}+ KCN \text { (excess) } \longrightarrow A \text { (cyano complex) } $
$NiCl _{2}+\text { conc. } HCl \text { (excess) } \longrightarrow B \text { (chloro complex) }$
The IUPAC name of A and B are
(a) potassium tetracyanonickelate (II), potassium tetrachloronickelate (II)
(b) tetracyanopotassiumnickelate (II). tetrachloropotassiumnickelate (II)
(c) tetracyanonickel (II), tetrachloronickel (II)
(d) potassium tetracyanonickel (II), potassium tetrachloromickel (II)

• A. potassium tetracyanonickelate (II), potassium tetrachloronickelate (II)
• B. tetracyanopotassiumnickelate (II), tetrachloropotassiumnickelate (II)
• C. tetracyanonickel (II), tetrachloronickel (II)
• D. potassium tetracyanonickel (II), potassium tetrachloronickel (II)

Answer 1

Answer: (A)

A = $K_2[Ni(CN)_4 ]; B = K_2[NiCl_4 ]$
A : Potassium tetracyanonickelate (II)
B : Potassium tetrachloronickelate (II)