Q. The ionization energy of $L i^{2 +}$ is equal to

3399 197 KCETKCET 2007Atoms Report Error

A

$9 h c R$

49%

B

$2 h c R$

25%

C

$6 h c R$

10%

D

$h c R$

16%

Solution:

Ionization energy $= R c h Z^{2}$
$Z = 3$ for $L i^{2 +}$
$∴$ Ionization energy $= (3)^{2} R c h = 9 R c h$