The ionisation constant of ammonium hydroxide is 1.77 × 10-5 at 298 K. Hydrolysis constant of ammonium chloride is

Question

The ionisation constant of ammonium hydroxide is 1.77 × 10-5 at 298 K. Hydrolysis constant of ammonium chloride is (A)  5.65 × 10-10  (B)  6.50 × 10-12  (C)  5.65 × 10-13  (D)  5.65 × 10-12

Tardigrade Admin · Accepted Answer

Given that K b ( NH 4 OH )=1.77 × 10-5 K W =10-14 at 298 K K h ( NH 4 Cl )=( K W / K b )=(10-14/1.77 × 10-5) =5.65 × 10-10

Q. The ionisation constant of ammonium hydroxide is $1.77 \times 1 0^{- 5}$ at $298 K .$ Hydrolysis constant of ammonium chloride is

$5.65 \times 1 0^{- 10}$

$6.50 \times 1 0^{- 12}$

$5.65 \times 1 0^{- 13}$

$5.65 \times 1 0^{- 12}$

Given that $K_{b} (N H_{4} O H) = 1.77 \times 1 0^{- 5}$
$K_{W} = 1 0^{- 14}$ at $298 K$
$K_{h} (N H_{4} Cl) = \frac{K _{W}}{K _{b}} = \frac{1 0 ^{- 14}}{1.77 \times 1 0 ^{- 5}}$
$= 5.65 \times 1 0^{- 10}$

Q. The ionisation constant of ammonium hydroxide is 1.77×10−5 at 298K. Hydrolysis constant of ammonium chloride is

5.65×10−10

6.50×10−12

5.65×10−13

5.65×10−12