Question

The ionic product of water at $25^{\circ }C$ is $10^{-14}$. Its ionic product at $90^{\circ }C$ will be

• A. $1\times 10^{-14}$
• B. $1\times 10^{-12}$
• C. $1\times 10^{-20}$
• D. $1\times 10^{-16}$

Answer 1

Answer: (B)

The product of $H^{+}$ and $OH$ - ions in water at a particular temperature is known as Ionic product of water. It is denoted as $K_w$

$K_w=\left[H^{+}\right]\left[O{H}^{-}\right]$

The value of $K_w$ increase with the increase of temperature i.e. concentration of $H^{+}$ and $O{H}^{-}$ ions increase with increase of temperature, but it still exists in the range of $10^{-14}$

e.g. $25^{\circ }C1.00\times 10^{-14}$

$100^{\circ }C7.50\times 10^{-14}$