Question

The ionic product of water at $25^{\circ} C$ is $10^{-14}$. Its ionic product at $90^{\circ} C$ will be

• A. $1 \times 10^{-14}$
• B. $1 \times 10^{-12}$
• C. $1 \times 10^{-20}$
• D. $1 \times 10^{-16}$

Answer 1

Answer: (B)

The product of $H^{+}$ and $OH$ - ions in water at a particular temperature is known as Ionic product of water. It is denoted as $K_{w}$

$K_{ w }=\left[ H ^{+}\right]\left[ OH ^{-}\right]$

The value of $K_{w}$ increase with the increase of temperature i.e. concentration of $H ^{+}$ and $OH ^{-}$ ions increase with increase of temperature, but it still exists in the range of $10^{-14}$

e.g. $25^{\circ} C\,\, 1.00 \times 10^{-14}$

$100^{\circ} C \,\, 7.50 \times 10^{-14}$