Question

The ion that has $s{p}^3{d}^2$ hybridization for the central atom, is :

• A. ${\left[IC{l}_2\right]}^{-}$
• B. ${\left[I{F}_6\right]}^{-}$
• C. ${\left[IC{l}_4\right]}^{-}$
• D. ${\left[Br{F}_2\right]}^{-}$

Answer 1

Answer: (C)

${\left[IC{l}_4\right]}^{-}\to s{p}^3{d}^2$
${\left[I{F}_6\right]}^{-}\to s{p}^3{d}^2$
${\left[IC{l}_2\right]}^{-}\to s{p}^{3}d$
${\left[Br{F}_2\right]}^{-}\to s{p}^{3}d$