The inversion of cane sugar represented by C 12 H 22 O 11+ H 2 O arrow C 6 H 12 O 6+ C 2 H 12 O 6 is a reaction.

Question

The inversion of cane sugar represented by C 12 H 22 O 11+ H 2 O arrow C 6 H 12 O 6+ C 2 H 12 O 6 is a reaction. (A) Unimolecular (B) Second order (C) Zero order (D) First order

Tardigrade Admin · Accepted Answer

Inversion of cane sugar is pseudo first order reaction because conc. of H 2 O remain constant. So, rate of reaction doesn't depend on concentration of H 2 O. r=K'[C12 H22 O11]

Q. The inversion of cane sugar represented by $C_{12} H_{22} O_{11} + H_{2} O \to C_{6} H_{12} O_{6} + C_{2} H_{12} O_{6}$ is a ____reaction.

Unimolecular

Second order

Zero order

First order

Inversion of cane sugar is pseudo first order reaction because conc. of $H_{2} O$ remain constant. So, rate of reaction doesn't depend on concentration of $H_{2} O$ .
$r = K^{'} [C_{12} H_{22} O_{11}]$

Q. The inversion of cane sugar represented by C12​H22​O11​+H2​O→C6​H12​O6​+C2​H12​O6​ is a ____reaction.