The interval [1,7] is divided into 6 equal intervals and the value of ∫ limits17( x2 + x +1 ) dx using Trapezoidal and Simpson’s rules are respectively Δ1 and Δ2 then

Question

The interval [1,7] is divided into 6 equal intervals and the value of ∫ limits17( x2 + x +1 ) dx using Trapezoidal and Simpson’s rules are respectively Δ1 and Δ2 then (A) Δ1 = Δ2 (B) Δ1 > Δ2 (C) Δ1 < Δ2 (D) Δ1- Δ2 = 2

Tardigrade Admin · Accepted Answer

Verify Trapezoidal and Simpson's rules on problem

Q. The interval [1,7] is divided into 6 equal intervals and the value of $1 \int 7 (x^{2} + x + 1) d x$ using Trapezoidal and Simpson’s rules are respectively $Δ_{1}$ and $Δ_{2}$ then

$Δ_{1} = Δ_{2}$

$Δ_{1} > Δ_{2}$

$Δ_{1} < Δ_{2}$

$Δ_{1} - Δ_{2} = 2$

Verify Trapezoidal and Simpson's rules on problem

Q. The interval [1,7] is divided into 6 equal intervals and the value of 1∫7​(x2+x+1)dx using Trapezoidal and Simpson’s rules are respectively Δ1​ and Δ2​ then

Δ1​=Δ2​

Δ1​>Δ2​

Δ1​<Δ2​

Δ1​−Δ2​=2

Verify Trapezoidal and Simpson's rules on problem

Q. The interval [1,7] is divided into 6 equal intervals and the value of $1 \int 7 (x^{2} + x + 1) d x$ using Trapezoidal and Simpson’s rules are respectively $Δ_{1}$ and $Δ_{2}$ then

$Δ_{1} = Δ_{2}$

$Δ_{1} > Δ_{2}$

$Δ_{1} < Δ_{2}$

$Δ_{1} - Δ_{2} = 2$